Today is more windy than yesterday, will a return flight take the same time, less time, or the same amount of time to complete?
(The 'Google Riddles' are interview questions those who wish to get hired were asked).
Let's do a worked example. Lets say our plane has to travel 300 miles there and 300 miles back. It has a standard cruising speed of 600mph. In the case of no wind it will travel the 600 miles in 1 hour exactly. Simple enough. Let us say that the wind speed is 100mph so the plane will be wind assisted to 700mph and slowed to 500mph - Wind Assisted: 300 miles at 700mph takes 0.429 hours - Wind Slowed: 300 miles at 500mph takes 0.6 hours - Total Time: 1.029 hours
What is the angle between the big hand and the small hand when the time is 3:15?
(The 'Google Riddles' are interview questions those who wish to get hired were asked).
You turn the 7 minute one and the 11 minutes one at the same time. When the 7 one finishes, turn it again. When the 11 one finishes, you know that 4 minutes have passed, with 4 minutes to get to the desired 15, all you need to do now is turn the 7 minute hourglass again since it counted 4 minutes, and when it runs out it'll be exactly 15 minutes.
Four people need to cross a bridge in 17 minutes in the middle of the night. The bridge can only hold two or less people at any time and they only have one flashlight so they must travel together (or alone). The flashlight can only travel with a person so every time it crosses the bridge it must be carried back. Tom can cross in 1 minute, John can cross in 2 minutes, Sally can cross in 5 minutes, and Connor can cross in 10 minutes. If two people cross together they go as fast as the slower person.How can they cross the bridge in 17 minutes or less?
First Tom and John will cross (2 minutes). Then Tom will bring the flashlight back (1 minute). Next Sally and Connor will cross (10 minutes). Then John will bring the flashlight back (2 minutes). Finally John and Tom will cross (2 minutes). 2 + 1 + 10 + 2 + 2 = 17 minutes.
I have a clock in my house, on the wall.
On a summer's day I forgot to wind it and it stopped. Then I went to visit a friend who had a watch that was always right on time. After I stayed for a bit, I went home, made a simple alteration and set the clock just right.
Now how did I do this when I had no watch on me to tell how long it took me to come back from my friend's place?
Before I left, I wound the wall clock. Upon my return, the amount of change that I could see in the clock is how long it took to go to my friends place and come back, adding to that the time I spent there, which I know because the clock at my friend's place is accurate.
Subtracting the time of the visit from the time I was absent from my house, and dividing by 2, I obtained the time it took me to return home. I added this time to what my friend watch showed when I left, and set the sum on my wall clock.
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