One evening there was a murder in a house where there lived a married couple with their 2 children - their son and daughter. One of these four people murdered one of the others.
One of the members of the family witnessed the crime.
The other one helped the murderer.
These are the things we know for sure:
1. The witness and the one who helped the murderer were not of the same gender.
2. The oldest person and the witness were not of the same gender.
3. The youngest person and the victim were not of the same gender.
4. The one who helped the murderer was older than the victim.
5. The father was the oldest member of the family.
6. The murderer was not the youngest member of the family.
Who was the murderer?
The mother was the murderer.
We know from fact number three that the youngest person wasn't the victim, and from the fourth fact we know the youngest person wasn't the helper and from fact number six the youngest person was not the killer either. Therefore, the youngest person can only have been the witness. If we make up a chart there are now three possible combinations:
Oldest person (father) H H M
Next to oldest (mother) V M H
Next to youngest (son) M V V
Youngest (daughter) W W W
(H = Helper ; V = Victim ; M = Murderer ; W = Witness)
We can work out from fact number five that the father was the oldest and from fact two that the youngest person must have been the daughter. Therefore the next to the youngest must have been the son and the next to the oldest, the mother!
A man has three daughters. A second, intelligent man, asked him the ages of his daughters. The first man told him that the product of their ages (them all multiplied together,) was 36. After thinking the second man was unable to find the answer and asked for another clue. The first man replies the sum of their ages is equal to his house door number. Still the second man was unable to answer and asked for another clue. The first man told him that his youngest daughter had blue eyes, and suddenly second man gave the correct answer. What were the ages of the first man's 3 children?
Everything the 2 men say here is a clue:
3 daughters, product of their ages is 36, then he gives him an estimate that the second person knows but we do not (the house door number), when the second man needs one more piece of information, the first man tells him the youngest has blue eyes.
So to solve, you want to write down all the 3 numbers whose product is 36, then to find the last hint, knowing that there IS a youngest child...
The ages are 6, 6 and 1.
to solve, you want to write down all the 3 numbers whose product is 36.
1, 1, 36
1, 3, 12
1, 4, 9
1, 2, 18
1, 6, 6
2, 2, 9
2, 3, 6
3, 3, 4
Here's the hardest part, the fact that the doorbell clue was not enough to solve the puzzle means that if we add up each of these options, we get at least two results that are the same, and we need more information to decide which one.
These are
13: 1, 6, 6
13: 2, 2, 9
Then to find the last hint, knowing that there IS a youngest child, means the smallest child doesn't have another sibling in the same age, meaning that 2,2,9 doesn't work, and we are left with 1, 6 and 6.
A man is asked what his daughters look like.
He says: "They are all blondes except for two. They are all brunettes except for two. They are all redheads except for two.
How many daughters did he have?
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